In addition, calculate the mean and standard deviations within each group. Create side-by-side boxplots of these data (so each boxplot uses the same y-axis).In patients in whom the cells were cultured ex vivo for an extended period of time (cohort 1), the cell doubling times were days. A study by Morgan and coworkers used genetically modified white blood cells to treat patients with melanoma who had not responded to standard treatments. What would you report? What is an appropriate measure of central location for data that are really skewed? What is an appropriate measure of spread for data that are really skewed?.Construct a stemplot of for each site (here is where side-by-side stemplots would be helpful but not required) and then compare the distribution of suspended particulate matter between the two sites (remember to mention center and spread). An environmental study looked at suspended particulate matter in air samples (µg/m3) at two different sites. Describe the population for the study? Describe the sample? What concern is raised by the fact that only 25 of the 100 questionnaires were completed and returned? However, only 25 of the potential respondents completed and returned their questionnaires. There were 1000 employees who used the benefit. To evaluate satisfaction with this service, the counseling office mails questionnaires to every 10th employee who used the benefit in the prior year. An employer offers its employees a program that will provide up to four free psychological counseling sessions per calendar year. Outline the design of this study in schematic form. The other three cities served as controls. Multiple-risk factor intervention strategies were randomly applied to two of the communities. The Stanford Five-City Project is a comprehensive community health education study of five moderately sized Northern California towns. So negative 2 is less than orĮqual to x, which is less than or equal to 5. So on and so forth,īetween these integers. In between negative 2 and 5, I can look at this graph to see Negative 2 is less than orĮqual to x, which is less than or equal to 5. What is its domain? So once again, this function It never gets above 8, but itĭoes equal 8 right over here when x is equal to 7. Value or the highest value that f of x obtains in thisįunction definition is 8. Or the lowest possible value of f of x that we get What is its range? So now, we're notįunction is defined. Is less than or equal to 7, the function isĭefined for any x that satisfies this double Here, negative 1 is less than or equal to x Way up to x equals 7, including x equals 7. So it's defined for negativeġ is less than or equal to x. This function is not definedįor x is negative 9, negative 8, all the way down or all the way What is its domain? Well, exact similar argument. Is less than or equal to x, which is less thanĬondition right over here, the function is defined. So the domain of thisĭefined for any x that is greater than orĮqual to negative 6. Wherever you are, to find out what the value of It only starts getting definedĪt x equals negative 6. It's not defined for xĮquals negative 9 or x equals negative 8 and 1/2 or Is equal to negative 9? Well, we go up here. We say, well, what does f of x equal when x In R, how can you find the smallest value in a vector such that the proportion of data less than or equal to it is greater than a certain number Note, I am not looking to use the quantile function, since (I believe) this doesnt give the smallest values. Is the entire function definition for f of x. Right over here, we could assume that this Those values of x will be where our function is defined. What is its domain? So the way it's graphed set whats inside the square root to be greater than or equal to 0 and solve for x. One more point (0,6) would give 6>3 which is a true statement, and shading should include this point. If point is (1,5) you can do the same thing, 5 > 5, but this would be right on the line, so the line would have to be dashed because this statement is not true either. If you try points such as (0,0) and substitute in for x and y, you get 0 > 3 which is a false statement, and if you did it right, shading would not go through this point. So lets say you have an equation y > 2x + 3 and you have graphed it and shaded. LATIN CAPITAL LETTER R WITH CEDILLA, Rcedil ŗ, LATIN SMALL LETTER R. The has to do with the shading of the graph, if it is >, shading is above the line, and ). equals =-020E5, REVERSE NOT EQUAL, bne >, GREATER-THAN SIGN. Without the "equal" part of the inequality, the line or curve does not count, so we draw it as a dashed line rather than a solid line The "equal" part of the inequalities matches the line or curve of the function, so it would be solid just as if the inequality were not there.
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